Triangle lmn has been dilated to form triangle l'm'n'. what is the least amount of information needed to determine if the two triangles are similar? segments ln and l'n' are congruent, and segments mn and m'n' are congruent. angles m and m' are congruent, and angles n and n' are congruent. segment bc=b'c', segment ln=l'n', and angles m and m' are congruent. angle n=n', angle b=b', and segments bc and b'c' are congruent. i thought a was the correct answer but i might be wrong

As Triangle LMN has been dilated to form triangle L'M'N'. We have to find the least information needed to determine if the two triangles are similar.

Similar triangles have the same shape, but not necessarily the same size.

They can be proved similar by various criteria like AA, SSS, SAS.

In the first option, Segments LN and L'N' are congruent, and segments MN and M'N' are congruent. Only two sides are given congruent, which is not sufficient to prove it similar. This is not the correct option.

In the second option, Angles M and M' are congruent, and angles N and N' are congruent. "If two angles of one triangle are congruent to two angles of another, then the triangles are similar". Therefore it is the correct option to prove the given triangles similar.

In options 3 and 4, sides BC , B'C' are used which are not even included in the triangles LMN and L'M'N', so, they are not the correct options.

Therefore, Option 2 is the correct answer.

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺