Given the exponential equation 2x = 128, what is the logarithmic form of the equation in base 10? x = log base 2 of 2, all over log base 2 of 128 x = log base 2 of 128, all over log base 2 of 2 x = log base 10 of 2, all over log base 10 of 128 x = log base 10 of 128, all over log base 10 of 2

Given exponential equation is

Now question says to write the given exponential equation in logarithmic form.

To do that we use the following conversion formula

In this formula we see that base "a" remains at it's position but b and c switch.

So we will keep base "2" fixed at it's position and switch x with 128.

Hence final answer will be

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

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step-by-step explanation: