Awoman has 3000naira to spend. she buys items , which cost the same amount each . draw a table showing the number of items she can buy if they cost 2000naira ,300naira, and 600naira each

Remark

The general formula for this is

Number of items she can buy = N

Cost Per item = C

Total amount of money = T

Givens

T = 8000

C = 200 naira, 300 naira, 600 naira

N = ???

Substitute and solve

a 200 naira

N = 8000 / 200

N = 40 She can buy 40 items at 200 naira apiece

b 300 naira

N = 8000/300

N = 26.7 Normally you would round up, but she does not have quite enough money to buy 27 items. So round down. Answer 26 items at 300 naira apiece.

She has 0.7 naira left over.

C 600 Naira

N = 8000/600

N = 13.3 Again, you round down. So she can buy 13 items and there is 0.3333 naira left over

Note: I'm not familiar with the currency, so I don't know how to properly express the small amount she has left over. But the whole number is correct.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

34

step-by-step explanation: