Which expression is equivalent to 6x^2 + 13x + 5? a (2x+5)(3x-1) b (2x-5)(3x+1) c (2x+1)(3x+5) d (2x-1)(3x-5)

The signs of the x-term and the constant term are both positive, so the signs of the constants in the binomial factors must be the same and must both be positive. The only offering that meets that requirement is

... C (2x+1)(3x+5)

If you multiply that out, you get 6x² + 10x + 3x + 5 = 6x² +13x +5, as required.

The sign of the constant term is the product of the signs of the constants in the binomial factors: (+1)·(+5). We want a positive sign for the constant, so both binomial factor constants must have the same sign.

When the signs of the binomial factor constants are the same, the x-term constant will match them. Thus, for a positive x-term constant, both binomial factor constants must be positive.

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400