Which equation results from applying the secant and tangent segment theorem to the figure? 12(a + 12) = 102 10 + 12 = a2 10(a + 10) = 122 10(12) = a2

The secant and tangent theorem states:

If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

In the given figure DE is tangent and AD is the secant .Applying the THeorem we have:

BD.AB=DE^{2}

Substituting the values from figure

10(a+10)=12^{2}

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted