An engineer estimates that 30% of gasoline is used efficiently by a car. how many gallons, out of 20 gallons, are used efficiently?

We need to find 30% of 20 gallons.

1) We can write a proportion

20 gallons 100%

x gallons 30%

x = 20*30/100 = 6 gallons

2) Or we can write 30% as decimal.

30% = 30/100 = 0.3

0.3 of 20 = 0.3*20 =6 gallons

Answer 6 gallons are used efficiently.

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²