Diane is 23 years older than her daughter amy. in 6 years diane will me twice as old as amy. how old are they? pls be very thourough.

Amy is x years

Diane is x+23

after six years

Amy will be x+6

Diane will be x+23+6=x+29

(x+29)=2(x+6)

x+29=2x+12

x=29-12

x=17 Amy's age now

Diane = 23+17 = 40 years

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

step-by-step explanation:

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