Boc= 90-1/2 angle bac how to prove this ?

Alright, lets get started.

Please refer the diagram, I have attached.

∠ABC is given as y.

So, the ∠EBC will be 180 - ∠ABC.

∠EBC = 180 - y

As given in question, BO is the bisector of ∠EBC, it means ∠OBC will be half of the ∠EBC.

∠OBC = of ∠EBC

∠OBC = (180 - y)

∠OBC =

Similarly,

the ∠DCB will be 180 - ∠ACB

∠DCB = 180 - z

As given in question, CO is the bisector of ∠DCB, it means ∠OCB will be half of the ∠DCB.

∠OCB = of ∠DCB

∠OCB = (180 - z)

∠OCB =

In triangle OBC, the sum of the angles of the triangle will be 180.

∠BOC + + = 180

∠BOC +

∠BOC = =

As per upper triangle ABC,

or

Putting this value in value of ∠BOC

∠BOC =

∠BOC =

∠BOC = 90 - : Hence proved

Hope it will help :)

answer: your gay

step-by-step explanation:

you dont know math

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.