What is the perimeter of the triangle below? round to the nearest hundredth.

You're going to need to use Pythagoras' theorem to work this one out!

As you know, the perimeter of a triangle is just all the lengths of the sides added up.

We'll start with side AC first. We can see that A is (-8, -4) and C is (-6, -2). That means to get from A to C, we need to go 2 units to the right, and 2 units up. Which means we have our two sides to work out the length from Pythagoras' theorem. 2² + 2² = c², c = √8.

Now we'll move onto side AB. We already know A is (-8, -4) from above, and B is (-7, -8). That means to get from A to B, we have to go 4 units down, and 1 unit to the right. So once again: 4² + 1² = c², c = √17.

Lastly, we'll work out side BC. We know that B is (-7, -8) and C is (-6, -2). That means to get to C from B, we have to go 1 unit to the right and 6 units up. So, again: 1² + 6² = c², c = √37.

Now that we have all of our lengths, we simply just add them up!

√8 + √17 + √37 ≈ 13.03 units.

(I've also attached something to help you visualise how I worked it out.)

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step-by-step explanation:

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