Need ! show how you got it and explain if possible.

Area of the circle

A = πr²,

r is a radius of the circle.

Formula of the circle is

(x - h)² + (y - k)² = r²,

h,k are coordinates of a center of a circle.

(x - 2)² + (y - 3)² = 24

For this circle r² = 24.

A = πr², > A=24π is the exact value of the area.

A=24π≈ 75.40 is the approximate value of the area.

Formula of the circle is

(x - h)² + (y - k)² = r²,

h,k are coordinates of a center of a circle.

(x - 2)² + (y - 3)² = 24

For this circle r² = 24.

A = πr², > A=24π is the exact value of the area.

A=24π≈ 75.40 is the approximate value of the area.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.