Iwill vote most answer. me part a: factor x2a2 + 3xa2 + 2a2. show your work. (4 points) part b: factor x2 + 2x + 1. show your work. (3 points) part c: factor x2 − 1. show your work. (3 points)

Part A: Factor x2a2 + 3xa2 + 2a2. Show your work. (4 points)

Important: Use "^" to denote exponentiation: x^2a^2 + 3xa^2 + 2a^2. Here a^2 is common to all three terms, and so we have a^2(x^2 + 3x + 2). Further, a^2(x^2 + 3x + 2) factors further: a^2(x+1)(x+2).

Part B: Factor x^2 + 2x + 1. The factors are (x+1)(x+1). Check this through multiplication.

Part C: Factor x^2 − 1 = x^2 - 1^2 is the difference of two squares. The factors are (x-1)(x+1). You've got to memorize this identity.

answer: a

step-by-step explanation:

if xy ~ yz therefore xy would be the same length as yz

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: