For 2 hours, lia drove at the speed of 60 mph, and for the next 3 hours, at the speed of 50 mph. what was lia's average speed during this trip? a)53 mph b)54 mph c)55 mph d)56 mph e)57 mph

For 2 hours, Lia drove at the speed of 60 mph= 2 x 60 = 120 miles for 2 hours

The next 3 hours, at the speed of 50 mph = 3 x 50 = 150 miles for next 3 hours

Total 5 hours = 120 + 150 = 270 miles

Average = 270 miles / 5 hours = 54 miles per hour (MPH)

B) 54 MPH

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)