Write the equation of a line with a slope of -5 that passes through the point (1, -1).

In this question, we will use slope intercept form that is y=mx +b, where m is the slope and b is the y intercept .

For the given question . x=1, y=-1 and slope , m = -5

We need to substitute these values in slope intercept form and solve for b, that is

-1=-5(1)+b

-1 = -5+b

Adding 5 to both sides

b =4

So we have slope, m =-5 and b=4

THerefore required equation is

y=-5x+4

its 8

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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