An unusual number cube (with 6 sides) has the numbers 2, 2, 4, 4, 6, and 6 on its faces. it is rolled once. match the outcome to its probability. 1. p(2 or 4) 1 2. p(multiple of 2) 2/3 3. p(multiple of 3) 1/3 4. p(odd prime numbers) 0

Below is the given columns whose entries are to be matched.

1. P(2 or 4) 1

2. P(multiple of 2) 2/3

3. P(multiple of 3) 1/3

4. P(odd prime numbers) 0

Let us solve this question by taking one entry at a time.

1. The probability of getting 2 or 4 is: P(2 or 4)==

As there are 2 faces with 2 and 2 faces with 4 making the total number of required possible outcomes as 4, the making the probability

2. We see that every number on the six faces of the cube is a multiple of 2 (2,4,6), thus, the probability of getting a multiple of 2 is 100% or in other words:

P(multiple of 2)=

3. Likewise, Only 2 faces which have 6 are the multiples of 3, thus:

P(multiple of 3)=

4. There is not a single prime number on the faces of the cube. Thus, there is not a single odd prime number on the faces of the cube.

Therefore, P(Odd Prime)=

The above are the answers of the given question and the columns can thus be matched accordingly.

a) 0,0; 1,1; and 2,2

step-by-step explanation:

these have the exact same coordinates, thus they are the correct function.

for the free

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