Explain the difference between using the trigonometric ratios (sin, cos, tan) to solve for a missing angle in a right triangle versus using the reciprocal ratios (sec, csc, cot). i understand what the ratios are, i just do not understand how they would necessary be used to find a missing angle. i only know how to use them to find a side length.

hello!

sometimes you may be asked to find a given angle given only two sides of a triangle.

for example, you may have a given angle where you are given the opposite side and hypotenuse. you would divide the opposite side by the hypotenuse and multiply by the inverse sine, or the arcsine. this would give you the angle.

i hope this !

the distance between point a and point b is 6 units

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2