Assume a and b are whole numbers, and a> b. which expression has the least value?

a > b

A . a^5b^3/ab^4 = a^4/b

B. a^4 / a*a*a*a = a^4 / a^4 = 1

C. ab^2 / a^2b = b/a

D. b*b*b/b^3 = b^3/b^3 = 1

B and D, doesn't matter what values of a and b it's always equal 1

Lets say a = 2 and b = 1

A. a^4/b = 2^4 / 1 = 16/1 = 16

C. b/a = 1/2 = 0.5

So C has the least value

ab^2 / a^2b

y + 11 = (1/4)(x + 16)

step-by-step explanation: