In a given course a student receives preliminary examination grades of 81, 85, and 95. the final examination is weighed for one-third and the average of the preliminary grades is weighed as 2/3 of the final grade. what should the final examination grade be for a semester average of 90?

The average of the 3 grades = (81+85+95) /3 =87

This counts as 2/3 of the final grade:

87 * 2/3 = 58 points

For a grade of 90, they still need 90 -58 = 32 points

Let x = final exam score

The final exam is worth 1/3, so we get:

1/3x = 32

To get x, multiply both sides by 3:

x = 32 *3

x = 96

They need a 96 on the final exam.

answer: ff

f

step-by-step explanation: f

ff

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.