Here is a table of values for y = f(x)

we will look at each options

and we can verify it from table

(A)

it means that at x=1 , y=6

we can see that this is in the table

so, this option is correct

(B)

we know that domain is all possible values of x

we can see that we are given values of x as

-2, -1 , 0 , 1, 2, 3, 4 , 5, 6

so, these values will be domain only

so, this option is correct

(C)

It means when x=5 then y=-2

we can see that we are given when x=5 then y=12 in the table

so, this option is not correct

(D)

We know that

range is all possible values of f(x) or y

we can see that all possible y-value is table are

5, 6, 7 , 8 , 9 , 10 , 11, 12 , 13

so, these values will be only range

Hence , this option is not correct...........Answer

true !

step-by-step explanation:

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