Asap slopes of parallel and perpendicular lines 1) what is the slope of a line parallel to the line with this equation: 5x – 15y = 30 a) 1/3 b) 1/5 c) 2/3 d) 3 2) line 1 has the equation: y = 2/3x – 5 line 2 is parallel to line 1. what is the slope of line 2? type your answer as a reduced fraction, like this: 3/5 3) determine whether the pair of lines is parallel, perpendicular, or neither. x = 2 and y = -5 a) neither b) perpendicular c) parallel 4) determine which equation is in slope-intercept form for the line that passes through (5, 0) and is perpendicular to the line below. y = -5/2x + 6 a) y = 5/2x + 2 b) y = 5/2x - 2 c) y = 2/5x - 2 d) y = -2/5x - 2 5) determine the slope of the line that is perpendicular to the equation below. y = -3x + 4 type your answer as a reduced fraction, if necessary, like this: 3/4

1) Parallel lines have equal slopes.

We need to find the slope of the given line by solving for y.

5x - 15y = 30

-15y = -5x + 30

y = (1/3)x - 2

The slope of the given line is 1/3, so the slope of the parallel line is also 1/3.

2) Line 1 has slope 2/3.

Line 2 has slope 2/3.

3) Line 1 is a vertical line through x = 2. Line 2 is a horizontal line through y = -5. The lines are perpendicular.

4) The given line can is solved for y, so we can see its slope is -5/2. The slopes of perpendicular lines are negative reciprocals. The perpendicular line has slope 2/5. We have point (5, 0) which is (x1, y1) in the slope-point formula.

y - 0 = (2/5)(x - 5)

y = 2/5 x - 2

5) The given equation has slope -3. To find the negative reciprocal, write the slope as a fraction, flip it, and change the sign.

Slope of perpendicular line is 1/3.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47