Use the given data to find the minimum sample size required to estimate the population proportion. margin of error: 0.045; confidence level: 96%; and unknown

The formula to find the minimum sample size while testing population proportion is

n =

Where p is sample proportion. If there is no information about sample proportion then we take it as 0.5

ME = Margin of error = 0.045

z (α/2) = Critical z score value

This is z score such that P(Z < - z (α/2)) = α/2 and P(Z > z (α/2)) = α/2

α = 1 -confidence level = 1- (96/100) = 0.04

α/2 = 0.04/2 = 0.02

So we have to find z score such that

P(Z < -z (α/2)) = 0.02 and P(Z > z (α/2)) = 0.02

Using z score table to find probability exactly or close to 0.02

Probability value 0.0202 is closest probability value and the corresponding z score is -2.05

It means P(Z < -2.05) =0.02 and P(Z > 2.05) = 0.02

So we have z (α/2) = 2.05

Using all the given values into formula to find sample size

n = 0.5 * (1-0.5) (2.05/0.045)^2

= 0.25 * (45.5556)^2

= 0.25 * 2075.313

n = 518.82

Round the sample size to nearest integer we get

n =519

The minimum sample size is 519

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.