The length of a rectangle exceeds its width by 7 inches and the area is 30 square inches. what are the length and width of the rectangle?

Let's assume w represent the width of the rectangle.

Given that, the length of a rectangle exceeds its width by 7 inches. So,

length = w + 7.

Given, area is 30 square inches.

Since Area = l* w

So, we can set up an equation as following:

(w + 7 )* w = 30

w² + 7w = 30 By distribution property.

w² + 7w - 30 = 0 Subtract 30 from each sides.

Next step is to solve the above equation by factoring to get the value of w.

First step is to breakdown the constant - 30 into two multiples so that their addition will result the coefficient of w =7.

So, -30 = -3 * 10.

Addition of -3 and 10 will give 7.

So, next step is to replace 7w with -3w + 10w. Therefore,

w² - 3w + 10w - 30 = 0

(w² - 3w) + (10w - 30)= 0 Make the group of terms.

w ( w - 3) + 10 (w - 3) = 0 Take out the common factor from each group.

(w - 3) (w + 10 ) = 0 Take out the common factor (w - 3).

w - 3 =0 and w + 10 = 0 Set up each factor equal to 0.

So, w = 3 and - 10.

Width cannot be negative 10.

So, w = 3.

Now length = w + 7 = 3 + 7 = 10

Hence length of the rectangle is 10 inches and width is 3 inches.

phosphate, calcium ion, chloride ion, neon atom

step-by-step explanation:

stew reads at the fastest rate of 265 words per minute.

step-by-step explanation:

it's a given that felicia reads at 260 word per minute and on connie's graph we can see that she reads 200 words per minute. since stew's table tells us that he read 795 in 3 minutes, we can divide 795 by 3 to find out how many words he reads per minute.

795/3 = 265

stew reads 265 words per minute - he reads at the fastest rate since felecia reads at 260 words per minute and connie reads at 200 words per minute.

stew (265) > felecia (260) > connie (200)