What is the value of lim 2x+3/4x-5 a. 3/5 b. 1 c. 1/2 d. 0

First of all, thank you for sharing the illustration of this problem. Without the illustration it would be hard to come up with an answer, since there are various kinds of limit and your own, typewritten instructions did not specify which.

Here you're finding the limit as x approaches infinity. Both 2x and 4x (as shown in the illustration grow larger continually and without bound, as x increases. As this happens, the other terms (+3 and -5) are simply overpowered by the x terms. If you choose to ignore these other terms for this reason, then your expression will be

2x

and this approaches the value 1/2 as x grows increasingly large in the

4x original expression.

So the limit of that expression, as x grows large without bound, is 1/2.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice