What is the solution set for 2x+5y> -1 and 4x-3< -3?

PROBLEM ONE

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Solving for x in 2x + 5y > -1.

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Step 1 ) Subtract 5y from both sides.

2x + 5y > -1

2x + 5y - 5y > -1 - 5y

2x > -1 - 5y

Step 2 ) Divide both sides by 2.

2x > -1 - 5y

So, the solution for x in 2x + 5y > -1 is...

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Solving for y in 2x + 5y > -1.

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Step 1 ) Subtract 2x from both sides.

2x + 5y > -1

2x - 2x + 5y > -1 - 2x

5y > -1 - 1x

Step 2 ) Divide both sides by 5.

5y > -1 - 1x

So, the solution for y in 2x + 5y > -1 is...

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PROBLEM TWO

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Solving for x in 4x - 3 < -3.

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Step 1 ) Subtract 3 from both sides.

4x - 3 < -3

4x -3 - 3 < -3 - 3

4x < 0

Step 2 ) Divide both sides by x.

4x < 0

x < 0

So, the solution for x in 4x - 3 < -3 is...

x < 0

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- Marlon Nunez

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

where's the diagrams?