Jacob is solving the equation 3√3q = 27 for q. his work is shown. 3√3q = 27 √3q = 9 (√3q)^ = 9^ 3q = a q = b what are the correct values for a and b? (^ stands for squared)

The given problem is stated as below:

3√3q = 27

√3q = 9

(√3q)^ = 9^

(^ stands for squared )

3q = A

Therefore we have,

A = 9^

or, A = 81

Again it is given that,

3q = A

or, 3q = 81.

or, q = 81/3 = 27

q = 27

As per the problem q = B,

therefore we can conclude that B = 27

So by solving the problem we get the final answer as below:

A = 81 and B =27

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier