At a local clothing store, morgan finds they are having a storewide 40% off sale. she also has a $15 coupon which applies to her total purchase. when the sales clerk processes morgan's order, she first applies the $15 off coupon, then takes the 40% off the remaining balance. which order of the discounts is best for morgan.

Morgan should first take the 40% off then apply the $15 coupon

Lets say her total was $150.

If you take the 40% off first, you get $90

150 * .6 = 90 (since you are taking off 40% you are still paying the rest of the 60% so you can just save extra steps by multiplying by .6 and not .4)

Now you subtract 15 from that value.

90 - 15 = 75 If Morgan takes the 40% off first and then applies the $15 dollar coupon, she has to pay $75.

If she applies the $15 coupon first, her total before the 40% is $135

150 - 15 = 135

The total will come out to be $81

$135 * .6 = 81

If Morgan takes the discount first before applying the coupon she has to pay less and saves the most money.

dude thats to long figure it

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: