Arectangle has an area of x^3+5x^2+5x-2 square meters and a width of x+2 meters. find its length

A = Lw

L = ( x^3 + 5x^2 + 5x – 2)/(x+2)

Using Synthetic Division

-2 1 5 5 -2

-2 -6 2

1 3 -1 0

A = (x+2)(x^2 + 3x - 1)

L = (x^2 + 3x - 1)

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i