Jesse was ranked 64th in his graduating class of 180 students. at what percentile is jesse's ranking? (round your answer to the nearest whole number.) th percentile

Jesse's ranking is in the 65th percentile.

Since Jesse was ranked 64th in a class of 180, the number of people below him will be: = 180 - 64 = 116

Then, we'll use the formula (x + 0.5y/n) in solving the question. This will be:

= (x + 0.5y/n)

where,

x = 116

y = 1

n = 180

= [116 + 0.5×1)] / 180.

= 0.647

= 0.65

Therefore, he's in the 65th percentile.

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They were 64th so 180-64 = 116 students were below them.

x = 116, y =1

(x + 0.5y / n) = 116 + 0.5*1 / 180 = 116.5 / 180 = 0.647 = 64.7%

Rounded to whole number = 65% = 65th percentile

wheres graph

step-by-step explanation: