Arunning track in the shape of an oval is shown. the ends of the track form semicircles. what is the perimeter of the inside of the track? (π = 3.14) 260.00 m 347.92 m 372.00 m 435.84 m

The perimeter of the inside of the track is 435.84 m.

Given

A running track in the shape of an oval is shown.

The ends of the track form semicircles.

The diameter of the shape is 56.

The circumference of the circle is equal to two times of radius.

The perimeter of the circle is;

The length of the inside of the track is given as 130 m, and there are 2 sides is;

= 130 + 130 = 260m

Therefore,

The perimeter of the inside of the track is;

The perimeter of the track = length inside track + perimeter of the circle.

The perimeter of the track = 260 + 175.84

The perimeter of the track = 435.84 m

Hence, the perimeter of the inside of the track is 435.84 m.

To know more about the Perimeter of the circle click the link given below.

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Two semi circles would equal one circle.

The perimeter of a circle is PI x diameter.

The diameter of the circle is shown as 56 m

The perimeter of the 2 ends = 56 x 3.14 = 175.84

The length of the inside of the track is given as 130 m, and there are 2 sides so 130 + 130 = 260 m.

Total perimeter = 260 + 175.84 = 435.84 m.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

you never say the total so we cant find the percentage used for petrol

step-by-step explanation: