The population of a small rural town in the year 2006 was 2,459 population can be modeled by the function below where f (x) is the number of resident =s and t is the number of years elapsed since 2006 f(x)=2,459(0.92)^t

using the information given above, complete the following statements. the percent change is %. the percent change represents .

f(x)=2,459(0.92)^t

given equation is an exponential function and in the form of f(x) = a(1-r)^x

where 'a' is the intial population

'r' is the decay rate

'x' is the time

f(x) = a(1-r)^x

given function is f(x)=2,459(0.92)^t

1 - r = 0.92

r = 1 - 0.92

r = 0.08

r= 0.08 %

percentage change = 0.08%

percentage change represents the decay rate.

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632