Find the work done by a force f of 21 pounds acting in the direction < 2,5> in moving an object 7 feet from (0,0) to (7,0).

Please find the attachment for a better understanding of the solution provided here.

We have been asked to find the work done by a force F of 21 pounds acting in the direction <2,5> in moving an object 7 feet from (0,0) to (7,0).

As we can see clearly from the question above that the object moves exclusively in the direction of the x axis and thus, the component of the force acting is only the x component. So, our main aim will be to find the x component of the force. Once it is found we will simply multiply it with the distance travelled in the x axis to find the work done as asked in the question.

Let us call the x component of the force as .

From the diagram in the attachment, we can see that the degrees

Thus, feet

feet-pound

Thus, A is the correct option

Work done, W =  54.59 foot-pounds

Step-by-step explanation:

It is given that,

Force, F = 21 pounds

From the figure it is clear that,

Distance, d = 7 feet

Work done is given that,

W = 54.59 foot-pounds

So, the correct option is (A).

Hence, this is the required solution.

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )