If the first and third of three consecutive integers are added, the result is 87 less than five times the second integer. find the third integer

consecutive integers are 1 apart

3 of them are x, x+1, x+2

x is the 1st integer, x+1 is the 2nd integer, x+2 is the 3rd integer

if the first and third integer are added (add x and x+2 together), then the result is 87 less than 5 times the 2nd integer (-87+5(x+1))

basically

(x)+(x+2)=-87+5(x+1)

expand and nice it up

2x+2=-87+5x+5

addd like terms

2x+2=-82+5x

minus 2x from both sides

2=-82+3x

add 82 to both sides

84=3x

divide both sides by 3

28=x

we can now find the 2 other integers

x+1=28+1=29

x+2=28+2=30

the 3rd integer is 30

Your answer is 30

Hope this helps

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step-by-step explanation:

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