Eab and dcb are two right triangles. the figure has bed≅ bde. point b is the midpoint of segment ac. prove: eab≅ dcb

we know both triangles are right-triangles, so they must have a 90° angle somewheres.

we also know that B is the midpoint of AC, so the segments of AB = BC, so we know the triangles have that side in common length.

but we also know that the ∡BED = ∡BDE, so the triangles have that angle in common as well.

well, the angles made at the vertex B, namely ∡ABE and ∡CBD, can't be 90°, due to the inclination from the sides E and D, so the right-angles must be at vertices A and D.

∡BAE = ∡BCDANGLE

∡BED = ∡BDEANGLE

AC = BCSIDE

so the triangles are congruent by AAS.

table 1

step-by-step explanation:

1-16

2-32

4-64

8-128

all multiples of 16

im trinna find out'

step-by-step explanation: