20 points for answering ! baxter is thinking about buying a car for $18,500. the table below shows the projected value of two different cars for three years. number of years 1 2 3 car 1 (value in dollars) 17,390 16,346.60 15,365.80 car 2 (value in dollars) 17,500 16,500 15,500 part a: what type of function, linear or exponential, can be used to describe the value of each of the cars after a fixed number of years? explain your answer. (2 points) part b: write one function for each car to describe the value of the car f(x), in dollars, after x years. (4 points) part c: baxter wants to purchase a car that would have the greatest value in 9 years. will there be any significant difference in the value of either car after 9 years? explain your answer, and show the value of each car after 9 years. (4 points)

(0,18500)

(1,17390), (1,17500)

(2,16346.60), (2,16500)

(3,15365.80), (3,15500)

a.)

  (17390-16346.60)/(1-2)

-$1013.40

18500(a)^1=17390

17390/18500=a

a=0.94

(16346.60-15365.80)/(2-3)

-$980.80

18500(a)^2=16346.60

16346.60/18500=a^2

0.8836=a^2

a=0.94

car 1 is decreasing at a variable negative linear slope, but at a constant exponential rate of 0.94

(17500-16500)/(1-2)

-$1000

(16500-15500)/(2-3)

-$1000

car 2 is decreasing at a constant negative linear slope of 1000 annually

b.) car 1=f(x)=18500(0.94)^x

car 2=f(x)=18500-1000x

c.) car 1 would have the greatest value after nine years, at $10600.40, as it's value is decreasing by 6% annually while car 2's value is decreasing at $1000 annually. the difference in value between the two cars after nine years is around $1100, which is fairly significant. 

f1(9)=18500(0.94)^(9)

f1(9)=$10600.40

f2(9)=18500-1000(9)

f2(9)=$9500

1

step-by-step explanation:

it's the only multiple of both and the least

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25