Answer asap. i cannot get this right no matter how carefully i try to solve it lol

When we get a question with "probability of at least two the same" we should think of it as 1 minus the probability of all different.

Rather than dazzle you with chooses and factorials let's work our way up to it.

If there was only one lady, there's probability 1 no two will choose the same style.

With two ladies, the second has a 13/14 th chance of choosing a different coat.

With three ladies , the probability of all different is

With eight ladies, we get seven fractions. We'll do 1 minus to get "two or more the same":

Second choice

5 boys 12 watch styles

P(Two boys different),=11/12

P(Three boys different),=11/12 * 10/12

P(Five boys different) = 11*10*9*8/12^4 = .3819

P(two of five match) = 1 - 11*10*9*8/12^4 = .6181

last choice

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

image for option 4

step-by-step explanation:

i just know the internet