If x2 + y2 = 100 and dy/dt = 3, find dx/dt when y = 8. (enter your answers as a comma-separated list.)

Answer;

dy/dx = - or + 4 and y = 8

Explanation;

x² + y² = 100

when y = 8

Then, x² + 8² = 100

thus; x² = 100 - 64 = 36

x² = 36

therefore; x = + 6 or -6

2x (dx/dt) + 2y (dy/dt) = 0

x(dx/dt) + y (dy/dt) =0

When dy/dt = 3

= (- or + 6) dx/dt + 8 (3) = 0

thus; dx/dt = - 8 (3/6)

= + or - 4.

Answer; y = 8 and dx/dy = - or + 4

answer: this is not a question

step-by-step explanation: this is a answer

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: