Lots of points! will mark brainiest given triangle abc with a(-4, -2), b(4,4), and c(18,-8), answer the following questions. 1. write the equation of the line containing the altitude that passes through b in standard form. 2. write the equation of the line containing the median that passes through point c in slope-intercept form. 3. write an equation for the line containing a perpendicular bisector of ac in point-slope form

I just like doing these.

1. Altitude through B.

The altitude is perpendicular to the opposite side, AC here. So we need the perpendicular to AC.

We see AC has slope (change in y)/(change in x)

m=(-8 - -2)/(18 - -4) = -6/22=-3/11

The perpendiculars will have a slope that's the negative reciprocal:

n=-1/m = 11/3

So the point slope equation through B(4,4) is

y - 4 = (11/3) (x - 4)

3y - 12 = 11x - 44

11x - 3y = 32

2. Median through C

The median is the line segment from the vertex to the midpoint of the opposite side, here AB.

A(-4, -2), B(4,4), and C(18,-8),

Midpoint of AB is the average of the coordinates, ( (-4+4)/2, (-2+4)/2)=(0, 1)

Line through (0,1) and (18,-8) is

(y-1)(18 - 0) = (x - 0)(-8 - 1)

18(y-1)=-9x

2y - 2 = -x

x+2y = 2

x+2y = 2

3. Perpendicular bisector of AC in point slope form

In part 1 we determined the slope of the perpendicular to AC was

n= 11/3

A(-4, -2), B(4,4), and C(18,-8),

The midpoint of AC is ( (-4+18)/2, (-2+ -8)/2) = (7, -5)

Point slope form is thus

y - -5 = (11/3)(x - 7)

y+5 = (11/3)(x-7)

you cant answer this dummy

step-by-step explanation: