Mathematics, 15.07.2019 00:00 lilly9645
The following data calculate the correlation coefficient. then describe the correlation based on the correlation coefficient. x y 0 11 3 26 9 17 4 22 6 18
Answers: 2
. We would use the same formula to find the standard deviation for the y using the y coordinates and the mean of y. For the standard deviation for x we have 
. Simplifying that down we have 
and 
which means that the standard deviation for x is 3.36. Now for y: 
which simplifies down to 
which means that the standard deviation for y is 5.63. Keep going...we're getting there. Now we need to take each coordinate pair x and y and multiply (x - mean(x))(y - mean(y)) and add those products together. 
which simplifies down to 
. Now divide that 13.4 by the product of the 2 standard deviation values: (3.36)(5.63): 
. That quotient is .7083650512. Lastly, divide that number by n-1 or 4. That means that the correlation coefficient is .177. A really good correlation coefficient is close to 1. So .998 or even .863 is a good correlation. Our decimal is only .1, so the data is all over the place and the equation you could find on your calculator using the regression program would not fit these points very well at all.
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The following data calculate the correlation coefficient. then describe the correlation based on the...
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