Ten pieces of paper numbered consecutively from 1 to 10 are put into a hat. if three pieces of paper are drawn at random from the hat one at a time without being returned to the hat, what is the probability that all three will be even numbers

There are 5 even numbers from 1 to 10.

The number of ways to draw all even numbers is 5!/(2!*3!) = 10

The number of ways to draw from the hat is 10!/(7!*3!) = 128

Therefore the probability is 10/128 = 5/64 or roughly 7.81%

rounding to the nearest thousandth would be 452,000

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3