Some racquet balls are sold in cylindrical cans of three balls. each ball has a diameter of 2.25 inches. the can has a diameter of 2.25 inches and is 6.75 inches tall. find the volume of the empty space in the can. use 3.14 for p. round to the nearest hundredth.

Volume of 1 ball = 4/3 π r³ = 4/3 (3.14) (2.25 ÷ 2)³ = 5.961 in³

Volume of 3 balls = 5.961 x 3 = 17.883 in³

Volume of cylinder = πr²h = (3.14) (2.25 ÷ 2)² (6.75) = 26.825 in³

Empty Space = 26.825 - 17.883 = 8.94 in³ (nearest hundredth)

8.94 in³

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4