Match the range of the function f(x)=x^2x-1

Appears that you've overlooked the need to share the possible answer choices.

f(x)=x^2x-1 has a parabolic graph with vertex at (0,-1). This is also the location of the vertex. Because the coefficient of x^2 is positive, this graph opens up. Thus, the smallest possible y value here is -1. The range of this function is

[-1, infinity).

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336

hi there!

the answer will be d: 2