What was the initial amount of water in a barrel, in liters, if there are now x liters, y liters were lost, and 6 liters were added? pls explain a)x-y+6 b)y-x+6 c)x+y+6 d)y+x-6

The easiest way to start this problem is to note the number of liters in the barrel right now.

That's x

You add 6 liters to that amount

You get x + 6

From that y liters are lost.

Now your total is

x + 6 - y.

If you switch the order (which you should) you get

x - y + 6

A

the right system of equations to describe the situation would

be on the form:

x1 = 8000 + y1*t

and

x2 = 8000 + y2*t

where x1 and x2 represents the total money of imogene and her

friend respectively at the end of t years.

now for the value of amount earned, y1 and y2:

y1=8000*0.08

y2=2000*√(t-2)

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76