How many four-digit positive integers have exactly three same digits and at least one zero?

We must count how many four-digit positive integers have exactly three same digits and at least one zero.

We will see that are 36 numbers that meet these conditions.

The easier way to find this is if we just count.

For a four-digit number we can start with:

1000

We have a four-digit number, the zero repeats 3 times, and we have at least one zero, so this meets the conditions.

Similarly, we can construct:

1110

1101

1011

In the 3 cases, we have 3 same digits and at least one zero. At the moment we have 4 numbers that meet the conditions.

With  a similar approach we can see that:

2000

2220

2202

2022

Also meet the conditions, so we will see that for each digit {1, 2, ..., 9} we can construct 4 four-digit numbers that meet the criterion.

Then the total number of four-digit positive integers that have exactly three same digits and at least one zero is:

9*4 = 36

There are 36 of these numbers.

If you want to learn more, you can read:

link

Let's calculate first, how many such numbers there are, where the same three digits are different form 0.

Now, the numbers where there are three 0's. There are only 9 of those

So, there are such numbers.

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant

answer: i could not see part the question so ill explain how to get the answer

step-by-step explanation: for instance the distance she travele d is 10 and she traveled the same amout each mile so do 10 divided by how many miles she drove each time and you ge your answer.