Indicate the equation of the line meeting the given conditions. put the equation in standard form. containing a (1, 3) and b (0, 2)

A line through two points A, B can be found by the point-slope form of the formula:

(y-ya)=m(x-xa)(1)
and 
m=(yb-ya)/(xb-xa)(2)

where A(xa,ya), B(xb,yb) and m is the slope between points A & B.

Substituting
A(xa,ya)=A(1,3)
B(xb,yb)=B(0,2)

From (2)
m=(yb-ya)/(xb-xa)
=(2-3)/(0-1)
=-1/(-1)
=1

Substitute in (1)  : (y-ya)=m(x-xa)
y-3=1(x-1)
Distribute and simplify
y=x-1+3=x+2
or
y=x+2  (3a) equation required in slope-intercept form

x-y+2=0(3b) equation in standard form