The number of bacteria in petri dish a doubles every 10 minutes. the number of bacteria in oetri dish b doubles every 6 minites. if both petri dishes begin with the same number of bacteria, how mmau times greater will the number of bacteria in petri dish b be than the number of bacteria in petri dish a after one hour?

Givens
Petri Dish A sees a double ever 10 minutes
Petri Dish B sees a double ever 6 minutes

Consequences
A doubles 60 / 10 = 6 times.
B doubles 60 / 6 = 10 times.

Solution
If you work best with numbers then suppose there are 100 bacteria in both dishes at the beginning
A = 100 * 2^6
B = 100 * 2^10

A will have 100 * 64 = 6400 bacteria growing inside A
B will have 100 * 1024 = 102400 bacteria growing inside B

B/A = 102400 / 6400 = 16

There are 16 times as many in B than in A. <<<< Answer

The distance from point a to point c across the coordinate plane is aproxamatly 8.94 rounded to the nearest hundredth. you use a^2 + b^2 =c^2