The original "ferris" wheel, designed by george washington gale ferris jr., was built for the world's columbian exposition of 1893 in chicago, illinois. there were: 36 fully enclosed gondolas (passenger cars) that carried up to 40 passengers. this "ferris" wheel eventually left chicago and was relocated in st. louis, missouri in time for the 1904 louisiana purchase exposition. on may 11, 1906, it was demolished using a dynamite charge and sold for scraps. the circumference of the "ferris" wheel had to be large enough to allow for an arc length of 21.94ft between each gondola. what was the diameter of the original "ferris" wheel? * round to the nearest whole number.

A Ferris wheel comprises of compartments arranged around the circumference

The diameter of the Ferris wheel is approximately 251 feet

The reason the above value is correct is as follows:

The given parameters are;

The number of gondolas in the original Ferris wheel, n = 36

The arc length between each gondola, l = 21.94 ft.

The required parameter;

The diameter of the original Ferris wheel

Method;

Calculate the product of the number of gondolas and the spacing between each gondola to find the circumference

Divide the circumference by π to find the diameter

Solution;

The circumference, C = l × n

∴ C = 21.94 ft. × 36 = 789.84 ft.

The diameter, D = C/π

∴ D = 789.84 ft./π ≈ 251.41 ft.

The diameter, D, rounded to the nearest whole number is D ≈ 251 feet

Learn more about Ferris wheel here:

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step-by-step explanation:

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