Mathematics, 15.07.2019 13:30 TVASALLO31

Ababy gains 11 pounds in its first year of life. the baby gained 4 1/4 pounds during the first four months and 3 1/2 pounds in its second four months. how much did the baby gain in the last four months?

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Answers

The baby gains 3.25lbs in the last 4 months.

This problem can be solved by simple subtraction. Take the total amount and subtract the 4 month increments in order to find the find 4 months.

Total = 1st 4 months + 2nd 4 months + 3rd 4 months

11 = 4.25 + 3.5 + 3rd 4 months

11 = 7.75 + 3rd 4 months

3.25 = 3rd 4 months

Answer from: joe7977

Amount of weight gain in first year = 11 pounds

A year can be divided into three parts consisting of four months each.

According to the question;

The baby gained 4 1/4 pounds during the first four months and 3 1/2pounds in its second four months.

Let weight gained in third 4 month be 'x' pounds.

So;

=> Weight gained in first year = Weight gained in first 4 months + Weight gained in second 4 months + Weight gained in third 4 months

=> 11 pounds = 4.25 pounds + 3.5 pounds + x pounds.

=> x pounds = 11 pounds - 7.75 pounds

=> x pounds = 3.25 pounds

Therefore, the baby gain 3.25 pounds in the last four months.

Answer from: Quest

step-by-step explanation:

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Answer from: Quest

your exact question is kind of difficult to understand, so maybe an example will explain what you're supposed to do? i'll work through the first problem on the worksheet.

suppose you have a tray of 652 brownies, and you have 5 friends that you want to feed without picking favorites. how many brownies can you dole out to each of your friends in equal amounts? how many will be left over for you to eat?

what you're doing here is finding a way to arrange the number 652 as the sum of integer multiple of 5 and some remainder: $652=5q+r$

here $q$ ("q" for quotient) is the number of brownies each of your friends get, and $r$ is the remainder. that's the basic idea behind division.

we break up the number 652 into parts so that the leading digit stands on its own:

652 = 600 + 52

first we check if it's possible to hand out exactly 100 brownies to each friend. with 5 friends, this means we want to know if we can take out 500 brownies from the tray. we can do this 1 time because we have 600 brownies to take from, and when we do that we're left with 100 + 52 brownies to divvy up. so we know that

652 = 1*500 + 152

next we want to know if it's possible to hand out exactly 10 brownies per friend. if we can, we have to remove 50 brownies from the tray each time until we can't. we have 152 brownies left, and we know that 3(50) = 150, so

152 = 3*50 + 2

now we have 2 brownies left in the tray. is it possible to hand 1 out to each of your 5 friends? no, you'd need a minimum of 5 brownies to do that. so the last 2 are yours.

putting everything together, we found that

652 = 1*500 + 3*50 + 2

and we can rearrange this to write

652 = 5*100 + 5*30 + 2

652 = 5(100 + 30) + 2

652 = 5*130 + 2

so $q=130$ and $r=2$ .

you might be more accustomed to the table depicting the algorithm. that's just a compact way of organizing what we've done above. you can consult the image i've attached below.