Mathematics, 15.07.2019 17:00 lindsayrader9628
Asoma dos doze primeiros termos de uma pg de razão 3 é 265.720. determine o primeiro termo.
Answers: 1
![Sum=a1*[\frac{1-r^{n}}{1-r} ] \\ 265,720=a1*[\frac{1-3^{12}}{1-3} ]\\ 265.720=a1*[265,720]\\ a1=1](/tpl/images/0093/1972/10eda.png)
![Soma=a1*[\frac{1-r^{n}}{1-r} ] \\ 265,720=a1*[\frac{1-3^{12}}{1-3} ]\\ 265.720=a1*[265,720]\\ a1=1](/tpl/images/0093/1972/f673b.png)
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Asoma dos doze primeiros termos de uma pg de razão 3 é 265.720. determine o primeiro termo....
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