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Mathematics, 15.07.2019 19:00 MegRasmussen31

Which of the following equations is of a parabola with a vertex at (0, -5)? y = (x - 5)2 y = (x + 5)2 y = x2 - 5 y = x2 + 5

Answers

ansver
Answer from: sulemmaa
Put 0 for x in each possible choice and see which one gives you y = -5.

The appropriate choice is
  y = x² - 5


Of course, you know the vertex form is
  y = a(x -h)² + k
for vertex (h, k) and scale factor "a".
Then for (h, k) = (0, -5), this is
  y = ax² -5
Only one choice matches that: y = x² -5. (for a=1)
ansver
Answer from: mya1318
The equation
y =  {x}^{2}  - 5
will have a parabola with a vertex at (0,-5) as the y intercept is - 5. Remember, quadratic equations can often be written in the form
y = a {x}^{2}  + bx + c
Where a is the coefficient of the quadratic, b is the coefficient of the multiple and C is the vertex/y-intercept.
ansver
Answer from: sparkyjones02

767.9

Step-by-step explanation:

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ansver
Answer from: letsgetcookingblog

\bf ~~~~~~\textit{parabola vertex form} \\\\ y=a(x- h)^2+ k \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] ~\dotfill\\\\ y=(x-5)^2\implies y=(x-\stackrel{h}{5})^2+\stackrel{k}{0}~~\checkmark \\\\\\ y=(x+5)^2\implies y=[x-(-5)]^2\implies y=[x-(-\stackrel{h}{5})]^2+\stackrel{k}{0}~~\checkmark

ansver
Answer from: Flowershere121

Equation of parabola is y = x² - 5 .

Step-by-step explanation:

Given  : parabola with a vertex at (0, -5).

To find :  which of the following equations is of a parabola.

Solution : We have given  vertex at (0, -5).

Vertex form of parabola   y = a(x - h)² + k .

Where (h ,k ) is vertex

We have h = 0 , k = -5 .

Equation : y = 1(x - 0)² - 5

y = x² - 5 .

Therefore, Equation of parabola is y = x² - 5 .

ansver
Answer from: percent74

The equation that has a vertex in (0, -5) is the first one.

Step-by-step explanation:

A standard form second degree equation is given by the following expression:

y(x) = a*x^2 + b*x + c

For which the vertex coordinates can be calculated by:

x_{vertex} = -\frac{b}{2*a}

While "y" for the vertex can be found by applying this coordinate on the expression. Using this knowledge in each equation gives us:

1. y(x) = x^2 - 5

a = 1\\b = 0\\c = -5

Therefore the vertex coordinate is:

x_{vertex} = -\frac{b}{2*a} = -\frac{0}{2*1} = 0

y_{vertex} = 0^2 - 5 = -5

This parabola has a vertex in (0,-5).

2. y(x) = x^2 + 5

a = 1\\b = 0\\c = 5

Therefore the vertex coordinate is:

x_{vertex} = -\frac{b}{2*a} = -\frac{0}{2*1} = 0

y_{vertex} = 0^2 + 5 = 5

This parabola has a vertex in (0,5).

3. y(x) =(x+ 5)^2 = x^2 + 10*x + 25

a = 1\\b = 10\\c = 25

Therefore the vertex coordinate is:

x_{vertex} = -\frac{b}{2*a} = -\frac{10}{2*1} = -5

y_{vertex} = (-5)^2 + 10*(-5) + 25 = 0

This parabola has a vertex in (-5,0).

4. y(x) =(x- 5)^2 = x^2 - 10*x + 25

a = 1\\b =- 10\\c = 25

Therefore the vertex coordinate is:

x_{vertex} = -\frac{b}{2*a} = -\frac{-10}{2*1} = 5

y_{vertex} = (5)^2 - 10*(5) + 25 = 0

This parabola has a vertex in (5,0).

ansver
Answer from: meghan0123

The x, which is zero in this case will always be the number that goes on the inside of the equation, so far you have y=(x+0)^2 or y=x^2.

The y, which is negative will go on the end of the equation. So you get y=x^2-5

The equation is y=x^2-5 or C if it is multiple choice

ansver
Answer from: Messick127
The equation of a parabola with Vertex V=(h,k) is
y=a(x-h)^2+k
If the Vertex is V=(0,-5)=(h,k)→h=0, k=-5
Replacing h=0 and k=-5 in the equation above:
y=a(x-0)^2+(-5)
y=ax^2-5

Third option: y=x^2-5

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Which of the following equations is of a parabola with a vertex at (0, -5)? y = (x - 5)2 y = (x + 5...

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