What is the equation of a line that passes through point r(3,7) and has a slope of 6?

The answer in slope intercept form is y = 6x-11

If you want the answer in standard form, then it would be 6x-y =11

notes:
* Slope intercept form is y = mx+b
* Standard form is Ax+By = C


Explanation:

The given slope is m = 6
The line goes through (x,y) = (3,7)

Plug those three values into the equation below. Isolate b
y = mx+b
7 = 6*3+b
7 = 18+b
7-18 = 18+b-18 ... subtract 18 from both sides
-11 = b
b = -11

So because m = 6 and b = -11, this means y = mx+b turns into y = 6x-11

The answer in slope intercept form is y = 6x-11

To convert to standard form Ax+By = C, we just have to get all the x and y terms together on the same side. I'm going to move the y term to the right side and move the 11 to the left side

y = 6x-11
y+11 = 6x-11+11
y+11 = 6x
y+11-y = 6x-y
11 = 6x-y
6x-y = 11

The answer in standard form is 
6x-y = 11
which is a different way to write the same line

Aquadratic function is one of the form f(x)=ax2 + bx + c l, where a,b, and c are numbers with are not equal to zero.