Aschool bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second grade travel in the bus. how many ways can the students be seated if all the first-grade students occupy the first 3 rows?

answer:   78125

step-by-step explanation:

since, the total number of seats = 25

and, there are 5 rows of 5 seats.

number of students in first grade = 15

number of students in second grade = 5

also, all the first-grade students occupy the first 3 rows,

thus, in first row total number of possible arrangement = 15

in second row total number of possible arrangement = 15

in third row total number of possible arrangement = 15

in fourth row total number of possible arrangement = 5 ( because all the first grade students got their seats )

in fifth row total number of possible arrangement = 5

thus, the total number of possible arrangement of sitting in 25 seats = 15 × 15 × 15 × 5 × 5 = 3125 × 25 = 78125

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step-by-step explanation:

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step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.